以下是银行家算法在C语言中的实现：
#include <stdio.h>// 资源数量#define M 3// 进程数量#define N 5void calculateNeed(int need[N][M], int max[N][M], int allocation[N][M]) {for (int i = 0; i < N; i++) {for (int j = 0; j < M; j++) {need[i][j] = max[i][j] - allocation[i][j];}}}int isSafe(int available[M], int need[N][M], int allocation[N][M]) {int finish[N] = { 0 };int work[M];for (int i = 0; i < M; i++) {work[i] = available[i];}int count = 0;while (count < N) {int found = 0;for (int i = 0; i < N; i++) {if (!finish[i]) {int j;for (j = 0; j < M; j++) {if (need[i][j] > work[j]) {break;}}if (j == M) {for (int k = 0; k < M; k++) {work[k] += allocation[i][k];}finish[i] = 1;found = 1;count++;}}}if (!found) {break;}}if (count == N) {return 1; // 安全} else {return 0; // 不安全}}int main() {int available[M] = { 3, 3, 2 };int max[N][M] = { { 7, 5, 3 }, { 3, 2, 2 }, { 9, 0, 2 }, { 2, 2, 2 }, { 4, 3, 3 } };int allocation[N][M] = { { 0, 1, 0 }, { 2, 0, 0 }, { 3, 0, 2 }, { 2, 1, 1 }, { 0, 0, 2 } };int need[N][M];calculateNeed(need, max, allocation);if (isSafe(available, need, allocation)) {printf("系统是安全的\n");} else {printf("系统是不安全的\n");}return 0;}以上代码实现了银行家算法的主要逻辑。输入的数据包括资源的数量、进程的数量、可用资源、最大需求矩阵和已分配矩阵。首先通过calculateNeed函数计算出需求矩阵。然后通过isSafe函数判断系统是否是安全的。如果是安全的，则输出"系统是安全的"，否则输出"系统是不安全的"。
